Question

show work please

The maximum sustainable electric field strength in air is 3.0 x 106 V/m. (electric fields above this field strength will ionize the air and cause sparks to form). Find the magnitude of the maximum potential difference that can therefore be sustained between two parallel conducting plates separated by 1.49 cm of air. Select the correct answer O 13.1 kV O 54.6 kV 0 20.1 kV 44.7kV 33.3kV

Answer 1

Electric field strength here is given as = potential difference (Voltage) / distance between the conducting charges

ttt LE đ 1. 49 cm of air paralles Electric field strengh in air which is between two conducting plates separated by distance 1.49cm = 1.49x10² m the maximum alwowable Electric field strength is 3.0x168 upto which spark does not E = Eleonic field = Voltage strength distance occur ,! 3.0x10 - Voltage Distance Voltage 1.49410-2 Voltage 6 3.0x10 X 1.49810 144700 V mo 2

therefore , the maximum allowable potential difference that to be sustained between two parallel conducting plates is 44,700 V or 44.7 KV so the correct option is D) 44.7 kV