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A machinist wished to insert a silver ride with a diameter of 6 mm into a...

A machinist wished to insert a silver ride with a diameter of 6 mm into a hole with a diameter of 5.992 mm. By how much would the machinist have to lower the temperture (in C) of the rod to make it fit the hole?

silver = 19 x 10^-6
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Answer #1

Gimm Of = 5.992 da lax100 % Df Di (Hd DT) 5.992 - 1 CLAT > Dt - I - LOT 6 Di -> AT = -70:17°C lowered by 70917°C Aus The remp

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