Question

Two parallel rails with negligible resistance are 11.0 cm apart and are connected by a resistor of resistance

R₃ = 5.00 Ω.

The circuit also contains two metal rods having resistances of

R₁ = 13.5 Ω

and

R₂ = 15.0 Ω

sliding along the rails (see figure). The rods are pulled away from the resistor at constant speeds of

v₁ = 4.00 m/s

and

v₂ = 2.00 m/s,

respectively. A uniform magnetic field of magnitude

B = 0.0100 T

is applied perpendicular to the plane of the rails. Determine the current in R₃.

Two parallel rails with negligible resistance are 11.0 cm apart and are connected by a resistor of resistance R3 = 5.00 N. The circuit also contains two metal rods havir resistances of R1 = 13.5 12 and R2 = 15.0 1 sliding along the rails (see figure). The rods are pulled away from the resistor at constant speeds of v1 = 4.00 m/s and V2 = 2.00 m/s, respectively. A uniform magnetic field of magnitude B = 0.0100 T is applied perpendicular to the plane of the rails. Determine the current in R3. uA upward X X X X X X X X X X X X X X X X X X X X X X X X X tea X X X X X X KIX X X XX -R3 x X X X X X X X X X X X X X x X X X X X X X X X X X X X X x R R2

Answer 1

Ansules Given that dellom - 0.11 m R, = 13,51, R2=153, R3=52 V=4 mis It 13., - 3 m/s, 8 = 0.0100 T x XR X 44 mis If 850 [R3 V=2 m/s Y х 2 R RT 13.51 15r From that figure consider left loop -11 Bdy, -IR-TR-O consider the right loop Body - Iz R2 + I, R2 = 0 - 2 .. I2 = Il +13 (3) From cquation (1) Bd v, - (1, +13) R, -11R3 = Bdv, - IR - IZR, -I R350 (4) Forom equation (2) Iz = Bdv, RE above Value scebetitute in equation 4 + IlR3 R2 - edu, – I (R1 + R) – (Boket +Tea y Ri=0 Rz Bov, - II (BitR3) BdV RI II R₂R1_o R, R2 CSScanned with CamScanner

solue the equation Yielding II 0.0100 XOUX I = Bd (V, Rq - VR) R3 R1 + R₂ R₂ + R, R2 II- [4x15) - @x13,5)] (5x13,5) +(5x15) +(13,5x15) 11 0,0363 67,5+75+ 202,5 1 0,0363 345 I, = 0.00010521 A = 105x10-6A I, I = 105 MA CScanned with CamScanner