Question

Doogle HESSAGE HY INSTRUKTOR PUNITE VERON NET URCES mem Question The pendulum in the figure consists of a uniform disk with radius 16.0 om and mass 460 g attached to a uniform rod with length - 610 mm and mass 270 9. (a) Calculate the rotational inertia of the pendulum about the pivot point. (b) What is the distance between the pivot point and the center of mass of the pendulum? (c) Calculate the period of oscillation. by Muty Units (ha) Number Unts (c) Number US VM LEH LITER acer 19 190 112 FE FO 12 + S 36 S 4 13 9 0 E 6 8 7 0 W P e E Y R U T A 5 А S D F K G Н. 2 X < Z C V N М. B Home Pg Up ALGE Alt

Answer 1

Given, R = 16 cm, m=460g L=610mm, Mp=2709 (a) For disk, T-M12 - MILAN 2 0:460(0.1632 I- t 00460 (0. 77), 오 I= 0.273 +5.88x103) Id = 00278 kgom? For rod, 'I= mL n2² al m (2) 12 I= DL 12 (0.27)(0.62 3 3 IR = 0.0335 kg me for pendolom, I - Id+IR I = 0.312 kg m?

b) COM of disk = LY Ootim com of rode = 0•305m com of pendolom = MID+ MIR mtm - (0.460) C0278) + (0-270 (0.0335) (0:460) +00-27) 0.187 m all. of som Distance is T &T=8T 0.312 2T. (0.46.40.279.8X0.187 (mimogh T= 3.03 S.