Solution) The gravitational potential energy is given as
GPE = Gravitational Potential × mass
The dimensions for Gravitational Potential is [L^(2)][T^(-2)]
The dimensional Formula for mass is [M^(1)]
GPE = [L^(2)][T^(-2)] × [M^(1)]
GPE = [M^(1)][L^(2)][T^(-2)]
Option(A) is correct
GPE = [L^(2)][M^(1)][T^(-2)]
In Si units, the derived dimension for gravitational potential energy is: Select one: O A. GPE...
Part A Select the equation that shows that the gravitational potential energy of a 1300-kg boulder raised 4 m above ground level is 52000 J. (You can express g in units of N/kg, because m/s? is equivalent to N/kg) mgh = (1300 kg)(10N/kg) (4 m)-52000 J 2 2 421) N2000J 0 PE-yMgh-V(1300kg)(10N/kg)(4m) o PE-mg-(1300 kg)(10 N/kg) (4 m) 52000 J PE = mgh = (1300 kg)(10 N/kg)(4 m) = 52000 J Submit Provide Feedback Next >
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