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Note: for this problem, you must show all of your work for full credit. 5. A 74kg basketball player performs a vertical jump
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Answer #1

Using work energy principle

KE = PE

0.5mv^2 = mgh

v = sqrt(2gh)

= sqrt(2*9.8*0.44) = 2.94 m/s

By using projectile

v^2 - u^2 = 2gH

0 - u^2 = 2*-9.8*0.44

u = 2.94 m/s

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