Question

9.0×1015 electrons flow through a cross section of silver wire in 380 μs with a drift speed of 7.8×10−4 m/s . What is the diameter of the wire? Express your answer to two significant figures and include the appropriate units.

Answer 1

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*** we have given, No. of electrons = 9.0x1015 time taken to cross = 380 MS the cross sectional Area Drift Speed (va) = 7.8x109 m/s To determine the diameter of the wire :2. Electron no.density of Silver (n)= 5.8x10 Pelechows/m2 * The number of charge carriers in a volume element it Ne=AAN Ne=nA Va at where is number den density (A) is circular cross Hallva -sechonl Area d²- 4Ne At time taken Tin Vaat d = (4x9x10's ITX (5 88018) 7-8X174x (380x105)] d = 6.666x107 m Neon d2vaat Vd- drift speed *** 7 dx 8.16x10 m

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