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3. The critical angle for total internal reflection at a liquid-air interface is 48.6. If a ray of light travelling in the l
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Ansal air(4.1) 8= go diquid ( ica criticle angle = 48.6° snells how Sin ic Ma Sinr Me Sin(48.60) = 1 singo Me - Me= 1:33. Siwil airl lla=1) liquidle) i = 40 Sini sint Me the = [sin40 Sui - sink - Sing= 0.856835884 2)&=sin (0-856885884) til; 18:58. 9

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