Question

1. A 140 g baseball is moving horizontally to the right at 35 m/s when it is hit by the bat. The ball flies off to the left at 55 m/s, at an angle of 25⁰above the horizontal. If the baseball remains in contact with the wall for 0.1 sec, what is the force exerted on the wall?

7) A 140 g baseball is moving horizontally to the right at 35 m/s when it is hit by the bat. The ball flies off to the left at 55 m/s, at an angle of 25° above the horizontal. If the baseball remains in contact with the wall for 0.1 sec, what is the force exerted on the wall?

Answer 1

ex initial 1 0250 25 there relocity of ball = 35 m/s sy- 55 m/s = final & 55 m/s bat 0 => angle with the horizontal surface V = 35m/s Vg x = -55 cos 25' - 55 X 0-91 m)8 - 49.85 m/s $) ༡༢༡ ufy = 55 sings = 23.24 ms x = -55 w125 change of momentum xane's is - here muain m=0.140 kg Px = 0.140 [-49.85-357 Px = -11.9 N.S change of momentum along y anis is Py = [upy a vig) Mwigao = 0.140 X 23.24 Net change of momenting pad P² + Pyn = Py = 3.25 Nos along Par muxs P= P²t Page = 11:9) ² + ( 3.25)2 rega P= 12.34 N.S on the wall Be in force exerted t=o.l see F- Р 12.34 F- 123.4N/(ans)