Question

A box slides from rest down a frictionless ramp inclined at 38.0° with respect to the horizontal and is stopped at the bottom of the ramp by a spring with a spring constant of k = 2.00 x 104 N/m. If the box has a mass of 12.0 kg and slides 3.00 m from the point of release to the point where it comes to rest against the spring, determine the compression of the spring when the box comes to rest. m point of release compression of spring

Answer 1

K = 2.00 *18 D haxsimo { 12.0kg x = 3.0m Let, the compression of springs .: Potential energia stored in the spring after compression - ₂ KS² Potential energa of the box at a height na mgh mgasino using conservation of energy, 2 Ž K 2 max asino amgxsino sa 2xsin (380) x 12.0x 9.818 3.0 2.00 x 104 K =0.0217 . s = 0.147m - 14.7 em B I Potential energy at point A = Mgh The potential energy will be convered into kinetic energy, when the block will reach B. That Kinetic energy will be used by the block to reach the point c. Atc, centrifugal force acting my mor mer on the brock 2 phone As the block is in contact with the surface 7 or, u pig ago

:using of energy conservation Angh - ngar 5 mg sh - 222 สุว 2. h - Sye 2