Question

Light containing wavelengths of 400 nm, 500 nm, and 650 nm is incident from air on a block of crown glass at an angle of 42.1°. (Assume crown glass has refractive indices of

n400 nm = 1.53,

n500 nm = 1.52,

and

n650 nm = 1.51.)

(a) Are all colors refracted alike, or is one color bent more than the others?

400 nm light is bent the most

500 nm light is bent the most    

650 nm light is bent the most

all colors are refracted alike

(b) Calculate the angle of refraction in each case to verify your answer. (Enter your answer to at least two decimal places.)

θ400 nm=

°

θ500 nm=

°

θ650 nm=

Answer 1

a> n 400 1.53 1500 = 1.52, 650 = 1.51 From Snell's Now n sin or 1 xsin oi sin og 1 x sinoi n As Oi is same for all o denotes berling OY i sin Oy a Yn O + Og ago 0=gö Oy Og Jolence for which n is largest have smallest as a sin" (in) wavelength increasing light greater "400 g > 50 sin in an with function. Itence & bending will be most for n. .As 400 nm light in bent the most. option ) 400 nm light a bent the most sin' sin oi For 22400 nm, 400 sin sin 42.1 1.53 400 > 25.988 2 25.99 For 500 nm, o 500 = sin sin 42.1 1.52 : 0.500 26.17° Fy x= 650um, sin Sun 42.1 :.0650 > 26.36 1. 0400 < 0.goo < 0650 As bending o = 90 - og (0) 400 - 640i Ob svo = 63-83 (06.400 (%),oo > (62.50 = 63.64°