Question

Exercise 9.47 - Enhanced - with Solution A pulley on a frictionless axle has the shape of a uniform solid disk of mass 2.60 kg and radius 20.0 cm. A 1.50 kg stone is attached to a very light wire that is wrapped around the rim of the pulley (Figure 1), and the system is released from rest. How far must the stone fall so that the pulley has 4.50 J of kinetic energy? Express your answer with the appropriate units. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of An unwinding cable ii. μΑ ? h = Value Units Submit Request Answer Figure Part B < 1 of 1 What percent of the total kinetic energy does the pulley have? Express your answer in percent. pulley V AC ? Кр Ktot % Submit Request Answer stone Provide Feedback

Answer 1

Stone man mz 1.5 / solution Part A Pulley kinetic Energy is 4.50J 9.47) mass (m) = 2.60 kg, radius r. 20cm= 202102m. losing Ź I w?= 4.5, I is moment of inertia of dell' 올알 et mr²w ²- 4.5 rwav yosxY =) M = v= 4.5x4 2.63 misec 2.60 fall Total Energy Pulley a) v2= + mv² = 4.5 when stone will be conserved K mass + mgh , g29.81 miseca L Kinetic Energy =) Ixlog x 6.923 & 4.5 = 105x9.818 h h= 0.45am ů / 0.658m 1 Kinetic obh Percent Part B Energy pulley how KP mRw²/4 mw²R²2+ MR²w²/y K total mw M + 2m/m M+2m 2.60 2.60+ 105x2 2060 5.60 46.43%