Question

A region of space contains a uniform electric field, with a constant magnitude E and directed along the positive x-axis. Part A - Which figure below correctly describes the electric potential as a function of x? O ☺ O

Answer 1

First we need to know about the relation between electric field and potential, which is given as

$\newline V_{b}-V_{a} = \int_{a}^{b}\overrightarrow{E}\overrightarrow{dl}$

Here the electric field is constant, then the potential difference will be

$\newline V_{b}-V_{a} = \overrightarrow{E}(b-a) \newline \newline Let \hspace (b-a) = x \newline \newline V_{b}-V_{a} = \overrightarrow{E}x \newline$

The potential difference is directly proportional to the distance for constant electric field in this case.

Option A will be correct

a)

Thank You !!!