Question

Ray Optics 1 Problem Statement Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (b) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? (c) As it leaves the glass, by what distance is the path of the ray is displaced from what it was before entering the glass? Visual Representation • Draw a ray diagram • Draw a line normal to the boundary • Show the ray bending in the correct direction • Label angles of incidence and refraction measured from the normal Mathematical Representation • Start with Snell's law and/or the law of reflection • Substitute in the known values • Solve for the desired unknown Check units and assess if your answer is reasonable

Answer 1

encadence of phface angle of sefracton Visudet representation: Let îi be the angle of Led r. be ther the an. angle from AB face. Then the do was evident Coface weth finally the rey was refracted et angle from eo face. are (No=1) A B. th grass (g=1.6) एम 1 R D T S NT = normal at AB face RSS normal at en face. From leles calculation, we get = 56 30- 71° a re

(a) For the refraction at Q, we have from Suelis law, Inodent Ma zen ? med.won Refreeted senli My sro 0. median 01 9. 2 Mg So here (s ruso) x = 30.710 This is the angle of refraction er enside the glen. Sie (6 from Snellin law of refrect on at R , مر - Ma se i 2 Mo 4 Mg senda here, madent medium The perdang Refracted medium, Now here, NT 11 RS. the ray DR cute them. So taro r. - Now from Mg or re- Ma non. orniriga Mg > Mgr. so a 12 2u Dr

de in a Mg ... ) 1.5 2in 30.7 20-50 FEU-om in the final i Soº angle of refraction the air () forom the chagren, leterd diska displacement -TR. We know that, wa t sen [ Here, t- willh of the plete Me 1.5 - Mga i = 50° na 5 russo) -(500) Vaige - sen 16.0 In = 1.92 en - The light from it's displeced u- (-92 con dregenal path. Sed
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