Question

H 11. A skier of mass 82 kg starts a downhill run from the top of a straight hill. The hill has a rough surface and has a length of 112 m. The top of the hill is 37.5 m above the lowest point. The speed of the skier at the top of the hill is - 183 and coefficient of kinetic friction between the skier's skis and the hill is 0.12. How fast is the skier moving at the base of the hill?

Answer 1

31 m= 82 kg L: 112m H. 37.5 m V = 1.8 km/h Mk = 0.12 Sin G=H @ = sinni 37.5 112 е た 19.56° Ina-dion =ma. mg sine Iny-disin N= mg Cas ☺ mg las f= Mx N = Mx mg Cose Put @ in mg sino - Using Gst = ma Gse xulk a=g sine og a - 9.81 (sin 19.56°– 0,2 G81956) a=2.175 m/s2

As we know equation of motion V2-y2= 295 V2_1118x1000 = 2x2.175x112 3600 2 y2-0.25 = 487.2 v= 22.08 mis V= 22. the speed of skies at base of hiell 22.08mis, hende, the the