Question

Problem ten: Cylinders with equal cross-sectional areas contain different volumes of an ideal gas sealed in by pistons. There is a weight sitting on top of each piston. The gas is the same in all four cases and is at the same temperature. The pistons are free to move without friction B C 2N D ION 2N 2N 10N 2N ION -ION V=5 liters VS liters V3 liters V3 liters Rank the mass of the gas in the cylinders. 2 3 1 Greatest Explain your reasoning. OR All the same Least Cannot determine Zero

please answer with explain.

Answer 1

Using ideal gas equation, PV = nRT

Number of moles of gas, n = PV/RT

Pressure, P = F/A

n = FV/ART

area of cross section A and temperature T are same for gases in all the containers. The mass of the gas is more if it contains a greater number of moles.

Hence, mass of the gas, m α FV

For container A:

m α FV α 5 x 12 α 60

For container B:

m α FV α 3 x 12 α 36

For container C:

m α FV α 5 x 4 α 20

For container D:

m α FV α 3 x 20 α 60

the masses of the gases are related as: A = D > B >C