Question

given the information

Common constants: 9.81 m/s2 = gravity on Earth's surface 343 m/s = speed of sound (air @ 20°C) 1440 m/s = speed of sound (water @ 20°C) 1.21 kg/mp = air density (20°C, 1 atm) 998 kg/m3 = water density (20°C, 1 atm) 1 atm = 1.01 x 105 Pa 3 x 108 m/s = c = speed of light (vacuum) 1.661x10-27 kg = p = atomic mass unit Specific Heats: 2040 J/(kg °C) Cwater = 4186J/(kg * °C) = 1996]/(kg*°C) Heat of Transformation for H2O: Lv = 539 cal/g = 40.7 kJ/mol = 2256 kJ/kg LF = 79.5 cal/g = 6.01 kJ/mol = 334 kJ/kg Stefan-Boltzmann constant = o= 5.6703x10-6 W/(m2*K4) Cice = Cwater vapor Gas constant = R = 8.31 J/(mol*K) Avogadro's number = Na = 6.02x1023 mol-1 Boltzmann constant = kg = R/NA = 1.38x10-23 J

answer

Answer 1

Heat needed to convert ice at -11^oC to 0^oC,

Q₁ = mc_ice$\Delta$T = [0.355*2040*{0-(-11)}] J

= 7966.2 J

Heat needed to convert ice to water at 0^oC,

Q₂ = mL_f = (0.355*334*10³) = 118570 J

Heat required to convert water from 0^oC to water at 100^oC,

Q₃ = mc_water$\Delta$T' = {0.355*4186*(100-0)} J

= 148603 J

Heat required to convert water at 100^oC to steam at 100^oC,

Q₄ = mL_v = (0.355*2256*10³) = 80088 J

Heat required to convert steam at 100^oC to steam at 122^oC,

Q₅ = mc_steam$\Delta$T'' = {0.355*1996*(122-100)} J

= 14139.664 J

Thus, total heat absorbed, Q = Q₁+Q₂+Q₃+Q₄+Q₅

= (7966.2+118570+148603+80088+14139.664)

= 369366.864 J