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table 3 please and share work :)
Table 2 Measured values of t(Ux) and t(U) at the three frequencies (L = 3.3 mH, C = 0,39 JF, R = 100 22 ) f = 1000 Hz f = fra
ΔΙ = f(υ)-t(υ) = Pexp ω Δt = 2πf Δί tan-11 X, -Χ Ptheory C R
3. Data from Measurements #1 to #3 in Exp 8.2 are displayed in Figure 2. 0.00125 5.4977 2.75000X105.4974 A vota. CAM 0.00104

table 2 calculations if needed
ta to 1.25mg 0.00125 s 125 ms (signal) . We have t= 1 f f = IDOOH fo: 800Hz ims 300 LOOD You shed wave (ter te), Hte, 0.00125
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Answer #1

For f = 1000 Hz tlus) - 0.001255, t(u) = 0.001045 At=t(up) - tlo) 0.00125 - 0.00104 st = 0.000215 w = 2af = 21 (looo) = 2x3.1For f = frees at resonance, ou | X = X WL = 1 we w2 = 1 LC = LC (3:3x103)* (0.39x106) w z (3,3x103) (0-39x1000) 2.78.75 x 10for t=8000 Hz At tvel-Ho +(1.25810-4)=(164X10) - 0.39x104 [At = 00:39 x 10 w=27f 50240 mode = 2x3-14 x foro - Pexp = wat =

I hope you understand the calculations. For queries please ask in comments.

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