Angular momentum, L = Iω where I is the moment of inertia and ω is the angular speed.
According to law of conservation of angular momentum, Iω = a constant when net external torque is zero.
Hence, a change in moment of inertia results in a change in the angular speed.
When a dancer girl lowers her arms, her moment of inertia is decreased and thus her angular speed is increased.
** her spinning rate increases because her moment of inertia decreases.
A dancer girl is rotating over a turntable with her arms out stretched. If she lowers...
Emmy the trapeze artist flies through the air with her arms and legs stretched out, tumbling head over heels. As she rotates, she pulls her arms and legs close to her chest, as shown in the illustration As Emmy pulls her arms and legs in, how does her rotational inertia change? It increases. It decreases. It remains constant As Emmy pulls her arms and legs in, how does her angular momentum change? It increases It decreases It remains constant As...
4 A ballerina is spinning on one foot with her arms stretched out, when she pulls her arms in. Will the following quantities increase, decrease or remain unchanged? (Ignore air drag) (i) Her angular speed. Increase (ii) Her moment of inertia. Decrease (iii) Her angular momentum. Increase (iii) Her rotational kinetic energy. Increase. K1 = 1/2 I1ω1 ; K2 = 1/2 I2ω2 . Because I1ω1 = I2ω2 , it follows K2 = (1/2 I1ω1)(I1/I2) = K1(I1/I2) > K1 THE ANSWERS...
A figure skater is spinning slowly with arms outstretched. She brings her arms in close to her body and her moment of inertia decreases by 12. By what factor does her rotational Kinetic energy change?
A skater rotates at 3 revolutions per second with her arms stretched. What must she do to decrease her moment of inertia? Need more information stretch both arms and foot out. stretch her foot out.pull her arms in
A 50.0kg mass skater with her arms stretched out giving her a radius of 0.9m is spinning with an angular velocity of 15 rad/s. If she pulls her arms close to her body her new radius is 0.30m, what is her new angular velocity?
A 50.0kg mass slater with her arms stretched out giving her a radius of 0.9m is spinning with an angular velocity of 15 rad/s. If she pulls her arms close to her body her new radis is 0.30m. What is her new angular velocity?
A skater extends her arms horizontally, holding a 5-kg mass in each hand. She is rotating about a vertical axis with an angular velocity of one revolution per second. If she drops her hands to her sides, what will the final angular velocity (in rev/s) be if her moment of inertia remains approximately constant at 5 kgxm2, and the distance of the masses from the axis changes from 1 m to 0.1 m? O 3 04 07 06
An ice skater rotating in place on (essentially frictionless) ice extends her arms and as result loses 10% of her kinetic energy. There is no air resistance. Explain fully what has happened. By what percentage did she change her moment of inertia?
An ice skater spinning with outstretched arms has an angular speed of 5.0rad/s . She tucks in her arms, decreasing her moment of inertia by 29% . What is the resulting angular speed? rad/s By what factor does the skater's kinetic energy change? (Neglect any frictional effects.) where does the extra kinetic energy come from?
A figure-skater finishes her routine with a dramatic spin. Initially, she spins at a rate of 1.3 rev/sec. During this time, the figure skater has her arms stretched out. In each hand, she holds a mass of 2.3 kg at a distance of 0.65m from the center of her body. She then pulls her arms in so that the masses are tucked into the middle of her chest. The moment of inertia of her head-torso-legs remains fixed at 24 kg-m2....