Question

The Antarctica Department of Transportation is renowned for bad engineering and only now figured out that cars were unable to turn on flat friction-less roads. They have a new proposal that you have been selected to review for its physics merit. Because they are at the south pole, the magnetic field can be approximated as roughly vertical (perpendicular to the ground). Also at the poles of the earth, the field is at its strongest at roughly B = 65 uTesla (65 x 10-6 Tesla) upward. Since moving charged particles in a magnetic field travel in circles, they have decided that the cars should "charge themselves" each time they want to make a turn and discharge themselves when they want to move in a straight line. They don't say how this should be accomplished since in their words "That's not my job". A figure from their proposal shows a car of mass m = 1020 kg traveling at v = 10.73 m/s executing a turn of radius r = 44.6 meters. Car becomes neutral here Car becomes charged here M B = 65ut up V Which sign of charge should be carried by the car? O Positive O Negative meters. Calculate the charge required on the car to execute the turn as shown: Coulombs If we assume that the maximum charge you could generate on the car is 3.67 Coulombs, what radius of turn would you execute? Based upon your results, should the proposal be accepted? O No O Yes Submit Answer

Answer 1

La Giren, Giren, that 10% by v = 10.73 ml. m; 10 90 B = 65 MT Coutwards) r= 44.6 m. as TL حم a) sign is negative (a? x) The force auto outward But here iti turining for a positive charged which inwards An: Negative b ) mv Bq 1020 x 10.73 7 q = m v Br 3.775800 C lu 65x10-6 x 4 4.6