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Problem #15 (10 points) The stability of cl with respect to alpha, beta-plus and beta-minus decay is to be determined. The fo

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Answer #1

During alpha decay a helium nucleus separated from parent nucleus hence mass decreases by 4 and atomic number decreases by 2 hence

_{17}^{36}\textrm{Cl}\rightarrow _{15}^{32}\textrm{Cl}\;\;\;+\;\;\;\alpha

During beta plus decay a proton breaks into neutron therefore mass remain same but it's atomic number decreases

_{17}^{36}\textrm{Cl}\rightarrow _{16}^{36}\textrm{Cl}\;\;\;+\;\;\;\beta ^+

During beta minus decay a neutron breaks into proton hence mass remain same but number of proton in nucleus increases due to which atomic number increases

_{17}^{36}\textrm{Cl}\rightarrow _{18}^{36}\textrm{Cl}\;\;\;+\;\;\;\beta ^-

Hence correct

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