Question

RA Tha D Ind B TC

There is water being taken/pumped out of a swimming pool that it round. The pool has a radius of R= 2.52m and it currently filled to a depth of ha=3.52m. The drain hose has a radius of rc=0.0316m. The height of the water at point A is slowly decreasing at a rate of 6.18cm/per minute.

What us the velocity of the water through the drainpipe Vc=?

What is the height hd of the water in the vertical tube, while the water is flowing?

If the up,p gets jammed and blocks the flow, what happens to hd?

Answer 1

if pipe is jammed then, ho=ha VA = 6.18 60000 -0.001020ms! C at A and a VA. A» (A) = Ve Ar(e) *(2-82) = Vc K (0.0316) 6.18 x 100x60 Vc = 6.18 x 2.52X2 S2 6000X 0.031640.6316 Ve= 6.55 mst Bemollies equation (b) at at A and D applying 6 + P 12 + Pgna - X + f g hot pust ho - 8) + gha pool ! (0-00103206:552) +9-8x 3 52 - = 1.33m. 9.8 = 34.49-21,45 9.8 (2) ho Lenel of water will same