Question

At what angle in degrees is the first-order maximum for 445-nm wavelength blue light falling on double slits separated by 0.0550 mm? [-16.76 Points] DETAILS OSCOLPHYS2016 27.6.P.067. MY NOTES ASK YOUR TEACHER When dots are placed on a page from a laser printer, they must be close enough so that you do not see the individual dots of ink. To do this, the separation of the dots must be less than Raleigh's criterion. Take the pupil of the eye to be 3.6 mm and the distance from the paper to the eye of 38 cm; find the maximum separation (in cm) of two dots such that they cannot be resolved. (Assume the average wavelength of visible light is 555 nm.) cm How many dots per inch (dpi) does this correspond to? dpi

Answer 1

Given, 2=445nm de 0.05s0mm. we nooo, ma= sin(om) => Om = sin sin (2) for first order maxionum, m=1, Us > Sió () (445x809) 0-0550 X163 → 0 = 0.46358 Hence, the angular frasi position of 1st maximum is 0.463580 6a76: Given, n= 555xpo 9m, D = 3.6*17"m, d = 38*io?m he now, the Rayleigh contesion is given by 1-22 -> x 192x1555* 3-6x103 >OX 10881x104 rad. Finding the minimum distance the minimum distance we have two dots be resolved, 0-5 x = od *x = (1.991xco^) ( 38 x1ő? x = 7.15 XLD can cm Alow, solving pots per inen (api) dpi = 2.54 cm/inch x de; = 2.54cm/inch 7.15 x 103 cm dp: - 355 dots per inch. Dots per inch rinch = 35 dpi