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A lab tech builds a circuit as shown in the figure. Find the following. (Assume C1 = 25.0 pF and C2 = 3.13 uF.) 6.00 pF CUF C

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bor 11 caler Cider C, ter HH + av Given c, = 250r, c2=3. 13 per (a) Equivalence capacitance tere are connected in Grer and caso cillest Q = 47.484 nec c, (right) Qi-47.484 MC Now potential through CiciH) Vi= C 47-484106 25*106 » Vi= 1.899 v en parall0 Potential difference across each capacitor. cicleft) 0 1 47.484x to 6 CI 25x106 1. sqq v ci (right) 1 899 v 1.899 v Grer ca

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