Question

**Please Do Not Forget The Visual Representation. Thank You!!**

Problem Statement A 5.0-uC point charge is placed at the 0.00 cm mark of a meter stick and a -4.0-uC point charge is placed at the 50 cm mark. At what point on a line joining the two charges is the electric field due to these charges equal to zero? Visual Representation • Draw a sketch of the charge distribution. Establish a coordinate system and show the locations of the charges. Identify the point P at which you want to calculate the electric field. • Draw the electric field of each charge at point P. Use symmetry to determine if any components of Ē, net are zero.

Answer 1

Using formula for electric field we can calculate electric field due to both charges

Between two charges electric field is not zero

On solving equation 1 we found that total electric field is zero at r = 1.72 m towards q₂​​​​​​ from q₁

Or at r = - 7.2 m from q₁​​​​​​ towards left of q<sub>1
Charge 1 q == 5.0k( = 5,0x100c Given Charge 2 2 - 4.04C - .-4.0x10o distance between q, and q +7= 50 cm = 0.50m V2 you x X Diagram is this Change 1 is placed -४ ko x ro q ----- 92 ㅏ + at origion. We placed meter stick one point at origin 100cm x -Y and other towards the x-axis (rightward). Charge 2 is placed at middle Fof meter stick at point distance between w,and q, is 08=V = 0.som. Let et point. p between two charge is electric fielld is zero this point pis km away from origin (from one end of meter stick).

We will calculate electric field at this point p due to both Chargus Electric Held due to Fi ۹, is Electric field due to q is. Ez € = kq, KX 5X156 x2 d12 =Kqz 44-4Kieº) Б x?- 5(0.25.2- 2xXx!=0 (r-x)? (r-M)? H-1.25. - .:= 3, +Ě, 2 - -N-1.25 = 0 K(5x106) + 0 K( 4x10" (rong? x? or x = 172 2=-0-72 *(5x3ot) xxAxit (8-30) => so 5 22 total electric field is zero at 1.72m from origin (tvex axi) towards Chary 22 beyond or 6=0 at 0,72m left side from Charger, 1-rex-axis meter stick ES 4 (8-12 5(r-us=462 5184x² 28x) = 4h² 58²750_zrx=45 -) D 50-45-582-28x = 0 x 5(0.57 278(0-5)=0 T

on solving eq o me we found two values of a x= 1.72 m or V=-0.72m both values don't lies between two charges YLsx P2--0172m.at -1.72- E F2 2V2 my EU gi 1 Electric field is zero at either of point l at x=1.72m (at tve X-9x46) (atore x-arie) or at x=-0172m Electric field at any point between %, and V is not zero
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