Question

5. (-/6 Points) DETAILS SERCP11 22.3.P.007. MY A ray of light travels from air into another medium, making an angle of , = 45.0° with the normal as in the figure below. Air Second medium 18 (a) Find the angle of refraction , if the second medium is fluorite. (b) Find the angle of refraction @ if the second medium is crown glass. (c) Find the angle of refraction @ if the second medium is carbon tetrachloride. Need Help? Read it Submit Answer

a, b, and c please!

Answer 1

Snell's law of refraction states that

n_i/n_r = sin $\theta$ _r/ sin $\theta$ _i

Here n_i is the refractive index of the incident medium and n_r is the refractive index of refracting medium. Also $\theta$ _i is the incident angle and $\theta$ _r is the angle of refraction.

Now here

a) the refractive index of fluorite is 1.434 and that of the air is 1. Here given that $\theta$ _i = 45⁰

Therefore 1/0.434 = sin $\theta$ _r/sin 45

Sin$\theta$_r = sin$\theta$₂ = 0.697*0.707 = 0.493

Therefore $\theta$ ₂ = sin^-1 0. 493

$\theta$₂ = 29.54⁰

b) the refractive index of crown glass is 1.52

Therefore 1/1.52 = sin$\theta$₂/ sin 45

sin$\theta$₂ = 0.658*0.707 = 0.465

Therefore $\theta$ ₂ = 27.71⁰

c) the refractive index of carbon tetra chloride is 1.461

Therefore 1/1.461 = sin$\theta$₂/sin 45

sin$\theta$₂ = 0.684*0.707 = 0.483

$\theta$₂ = 28.88⁰