For the meter stick to be in rotational equilibrium, the clockwise moment about R should be equal to the anti clockwise moment about R.
Clockwise moment about R,
M = (Wm × Xcm) + (W2 × X2) + (W3 × X3)
Anti clockwise moment about R,
M = (W1 × X1)
So,
(W1 × X1) = (W2 × X2) + (Wm × Xcm) + (W3 × X3)
Also, the net force acting in vertical direction should be 0.
So,
W1 + W2 + W3 + Wm = R
These two equations are needed to find the condition for rotational equilibrium of the meter stick.
The equations for the rotational equilibrium for the meter stick in the image below is KX...
The meter stick in the drawing below is at equilibrium. The mass
of the meter stick is 100g, and the meter stick is uniform.
B only please, thank you.
Ocm 80cm 100cm m a)The mass m is: A. 100g а. 50g b. 200g с. 150g d. none of the above b) Find the support force
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Torques and Center of Mass. The
Experiment:
In this experiment, you balance a meter stick, to balance the
meter stick, attach masses at positions until the system is in
equilibrium.
The meter stick acts as if all its mass was concentrated at its
center of mass. With the fulcrum at the center of mass, r (the
distance from the axis of rotation to the place where the force is
applied) is 0, so there’s no torque due to the meter...