Question

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The resonant frequency of an RLC series circuit is 2.88 x 103 Hz. If the self-inductance in the circuit is 3.89 mH, what is the capacitance in the circuit? Colant honorant nnnn

Answer 1

we know, the resonant frequency of a series RLC circuit is given by

fr 27 VLC

Now, for f_r = 2.88 * 10³ Hz and L = 3.89 * 10^-3 H, we get

$2.88 \times 10^{3}=\frac{1}{2\pi \sqrt{3.89\times 10^{-3}\times C}}$

$C=\frac{1}{4\pi ^{2} \times 3.89 \times 10^{-3} \times \left ( 2.88 \times 10^{3} \right )^{2} }$

C= 7.85 * 10^-7 F =0.785 μF