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1. What is the pH of a 0.35 mol/L solution of acetylsalicylic acid (C9H804)?
What is the pH of a 0.35 mol/L solution of acetylsalicylic acid (C9H8O4) 1. What is the pH of a 0.35 mol/L solution of acetylsalicylic acid (C9H804)?
Maps 1. What is the pH of a 0.35 mol/L solution of acetylsalicylic acid (C9H804)? 2 points Your answer 2. What is the pH of a 1.50 mol/L solution of ammonium chloride (NH4Cl)? 2 points Your answer 4 points 3. What is the pH of the buffer resulting of the mixing of 34.4 g of sodium dihydrogen phosphate (NaH2PO4) and 48.5 g of sodium hydrogen phosphate (Na2HPO4) in 2.5 L of distilled water? Your answer 4. What is the pH...
1. What is the pH of a 0.35 mol/l solution of acetylsalicylic acid (C9H8O4)? 2 points Your answer
What is the pH of a 0.35 mol/L solution of facetylsalicylic acid 2
What is the pH of a 1 L solution containing 0.5 mol of propionic acid and 0.4 mol of sodium propionate? Ka for propionic acid = 1.3 x 10-5. Select one: O a. 4.8 O b. -1.3 C. 1.3 O d. -5.0 e. 5.0 O O O
Consider a weak acid "HA". What is the pH of a 0.853 mol L-1 solution of HA? The KA of HA is 6.32 x 10-6
What is the pH of a solution containing 0.831 mol L-1 of a diprotic acid with pKA1 = 4.62 and pKA2 = 8.62 ? H2A + H2O ⇌ H3O+ + HA- pkA1 HA- + H2O ⇌ H3O+ + A2- pkA2
What is the pH of a 5.00 times 10^-3 M solution of acetylsalicylic acid, pK_a = 3.52. (Enter your answer to 2 decimal places) pH =
Calculate the pH of a solution that is prepared by dissolving 0.500 mol of hydrocyanic acid (HCN, KA = 6.17x10-19) and 0.187 mol of acetylsalicylic acid (HC,H,04, K4 = 3.40x104) in water and diluting to 3.40 L. Also, calculate the equilibrium concentrations of HCN, CN, HC,H,O4, and C,H,O4. Do not make an approximation unless the initial acid concentration is greater than 1000 × K. (Hint: The pH will be determined by the stronger acid of this pair.) pH = [HCN]=...
A 0.1 mol/L hydrochloric acid solution has a pH of 1.0 while a 0.1 mol/L hydrofluoric acid solution has a pH of 2.1. If these two acids have the same concentration, why is there a difference in the pH of these solutions?