Calculate the mass of oxalic acid needed to make a 250.0 mL standard solution that is 0.0500 mol L-1 . You will use oxalic acid dihydrate, (COOH)2.2H2O. M((COOH)2.2H2O) = 126.07 g mol-1 )
Solution-
suppose w gram oxalic acid needed.
Volume = 250ml =250× 10^-3L=0.25L
Molar mass = 126.07 gram/mole
Moles =w/126.07 mole
Molarity = moles/volume
=w/126.07×0.25
0.0500=w/31.52
w=0.0500×31.52
w=1.58 gram.
Hence, 1.58 gram required.
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