Given,
L=15.8 m
@=5.5°
m=110 kg
(A) the period of pendulum,
T=2π√(L/g)
=2π√(15.8/9.81)
T=7.974 s
(B) Bob's maximum speed,
v= A•w { f=1/T , w=2πf ,A=L•sin@}
=L•sin@×2π/T
v=15.8×sin5.5°×2π/7.974
v=1.2 m/s
(C) maximum kinetic energy,
KE=½ mv²
=½×110×(1.2)²
KE=78.31 J
(D) by using conservation of energy,
The maximum displacement,
PE= KE
mgh=½ mv²
h=v²/2g
h=0.0726 m
In a science museum, you may have seen a Foucault pendulum, which is used to demonstrate...
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