Question

In the game of tetherball a rope with length L = 1.40 m connects a ball with mass m = 0.500 kg to the top of a vertical pole so that the ball can spin around the pole as shown in the figure. L 0 What is the speed v of the ball as it rotates around the pole when the angle 0 of the rope is 34.0° with the vertical? m U = 1.917 m/s Incorrect

Answer 1

1. The above problem is related to game of tetherball a rope with a ball to the top of the pole.
2. This problem requires the equilibrium of force for solution.
3. All the steps are clearly mentioned and easy to understand.
4. Hope the answer will help you. Thank you for your support.
5. 
   solution Given, In. a rope with length the game of tetherball L = 1.40 m et Connects ball with mass m = 0.500 kg to the top of a ventical angle 034, 0 I with the vertical drawing F.B.Do pole making an 0 Now dra Tension T' R Centrifugal force (mRw?) then Weight (mg) the tension in the ball rotates with angular velocity TRş Tsin (90-0) the rope T tet and 90-0 MRw?. Tcos (90-0) Now , mg Taking Vertical Force Equilibrium Efy = Tsin (30-0) - mg = 0
   
   → Tcoso = mg » T-mg 0.500 X 9.81 COS 34° = 5.916 N Again, {fy Taking horizontal force Equilibrium Tcos (90-0) - MRw² MR w ² Tsino From Triangle R = L sino R ni Tsino = m (L sino). w? 5.916 mL 6.500 X 1.40 w? A 3 = 2.907 rad/see Therefore ། speed v of the ball V=Rw = (Lsimo.co V 1.40 X Sim 34" x 2.907 v = 2.275 m/s