Question

212 312 Consider the resistive circuit shown in the figure to the right. Find: a) b) C) d) Reg Isys 24 V 482 152 I for the 422 resistor the power absorbed by the 192 résistor

Answer 1

2.2. 3-22 of 842 12 24V @ 332 and 12 ore in sercies so their equiva- lent resistance - R= 3+1 = 42 Now 48 and 42 are in o their equivalent 24 423 22 R= 41 Parallel.oc their R' 드 4x4 4+4 16:=2.2 22 Hunt R! 322 + Now ar and 2.2 are in seseies 50 Overall equivad lent resistance - = Rog Roqz42 b olm's low- Reg =2+2 By Isys = V Reg 24. = GA y C A АДААД -> I 32 B ДААД Iz It :452 I2 I= ) Is 12 T © at node B I; +12 0 -24v using Kivil. in the loop ABEFA- 21 +41, = 24 =) 201, + Iz) +41, = 24 6 I +2 I 2 =24 E D

2 using 31 + 1 =12 =) Iz = 12-31 KiviL in the look loop BC DEB 312 + 1 x T2 4I=0 41 Iz - Izo (3) eqi 41 05ے۔ using @ into eq 1 3 co 12-31, -1 41 ㅏ = 12 =) = 3 A so current in 48 leesistor = 3A 의 crocent in 12 resistor Iz = I, (by eq.02 = 3A Power absorbed by 1.2- P= I x R = (3) x1 2 = 9 W