Question

Problem ID: GriffithChapter14_04 Enter your 7 digit student id#: Student ID recognized A means your answer is correct A X means your answer is wrong A X means your answer is close but wrong (do not round off at all unless stated). Press the SUBMIT YOUR ANSWER(S) button, to save and send your work to your instructor, when you complete or partially complete this exercise. Two parallel wires, each carrying a current of 4 A, exert a force per unit length on each other of 4.3 x 10-5 N/m. (a) What is the distance between the wires? Part Answer Units X (a) Hint ות

Answer 1

Magnetic force between two current carrying wire is given by:

F/L = u0*i1*i2/(2*pi*d)

And force will be attractive if both wires have current in same direction and Force will be repulsive if both wires have

current in opposite direction

Given that

F/L = Force per unit length between wires = 4.3*10^-5 N/m

i1 = i2 = current in each wire = 4 A

d = distance between each wire = ?

So,

d = u0*i1*i2/(2*pi*(F/L))

Using given values:

d = 4*pi*10^-7*4*4/(2*pi*4.3*10^-5)

d = 0.0744 m

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