Question

A car having an initial velocity of 15 m/s accelerates with an acceleration of 1.50 m/s? until it reaches a final velocity of 30 m/s. How far must the car travel to reach its final velocity? O2. 250 m 6.275 m O4 225 m d. 300 m

Answer 1

Given:

$u=15\ \text{m/s}\\ a=1.50\ \text{m/s}^2\\ v=30\ \text{m/s}$

This is an example for constant accelerated motion. Then, the distance travelled by the car is,

$S=\frac{v^2-u^2}{2a}\\ =\frac{30^2-15^2}{2\times1.50}\ \text m\\ =225\ \text m$

Therefore, option c is the right answer.