Question

CAN SOMEONE HELP ME SOLVE THIS PROBLEM PLEASE!!

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« EQ Question 17 (2 points) An ideal solenoid is 250 cm long with a cross-sectional area of 1.00 x 10-4 m2 and has 800 turns of wire. (uo = 411 x 10-7 T.m/A). What is the self-inductance of the solenoid? (2 pts)

Answer 1

Ans

Length of solenoid L = 250 cm = 250 $\times$ 10^{- 2} m = 2.50 m

Cross-sectional area of solenoid A = 1.00 $\times$ 10^{- 4} m²

Number of turns of wire N = 800

$\mu$_o = Magnetic permeability of free space = 4$\pi$$\times$ 10^{- 7} T.m/A

Self inductance of solenoid is given by

$L' = \frac{\mu_o \ N^2 \ A}{L}$

$L' = \frac{4 \pi \times 10^{-7} \times (800)^2 \times 1.00 \times 10^{-4}}{2.50}$

$L' = 3.217 \times 10^{-5} \ \ H$

Please feel free to comment if you have doubt

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