Question

Sunny langles, at the base RT this JHB Math Lab 7c. With this -> 0°c o c360° 21) angle a.) Calculate sine. Is this calculation an angle or ratio of Sides? by using legs and hypo tenuse of or a RT triangle, why con Sin never be greater than 1.3 44 9=-374 cos (2x**) explain v mary cycles in der had. al. How by curve shifted left or RT? C) Curve Shifted up or down?

Answer 1

som 21) Given With 0°< 0 < 360° Angle Lut Assume the side of Triangle 3,4,5 в 5 4 A 3 We know that Simo AB Bc 5 Perkendicular hypotenous hypotenou = V (Porpemdiculoan)*+ (base) 0 = sin() 30. so. According to Ratio of side Simo= AB Bc 4 5 b) Using legs and hypotenous of a Right Angle Triangle hypotenous is greater thom other two sides and so thats why be greater than 1 Simo= So Demonitas is h>P Р h. Sime value is neven 41 Given equation Y = -3 + 4 cos (2x + 7 / 41 is in the form of ya Acos (B2C+c)+] Here Amplitude = 4 Period - 21 da 2 Increment B Period 4 -

2x= KIM 3 Phase shift (2x + 5) = 0 => x=-776 (Towards Right) vertical shift tops D = -3 ( down wand) Imax = A +D = 4 +(-3) = 1 y = A-D = 4-(-3) = 7 Now. x1-7 | 그지 5* 6. 13TL 4T 197 12 3 12 117 6 12 12 . wla 1 -7 1-3 -3-71-3 1 -3 --- ng 0 4T/3 11746 STYL 19712 7/12 / 772 - kle -2 - 5 -6 al No b) of cycle = 2 Curve shifted towards Right curve shifted downward