Question

An analytical chemist is titrating 104.4 mL of a 0.5000 M solution of cyanic acid (HCNO) with a 0.5500 M solution of NaOH, The p Ka of cyanic acid is 3.46. Calculate the pH of the acid solution after the chemist has added 103.6 mL of the NaOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of NaOH solution added. Round your answer to 2 decimal places.

Answer 1

104. 4 out of o. 500 M HCHNO E 0.500 mer 0.10 & 4ht X I lit = 0.0 522 men. 103.6 me of 0.55 00 M Nara 0.55. mer 0.103 64t t wit = 0.0 5.69 mor. HeNot Nach Nacno & tho B 0 0522 0.0 569 6 -0.0522 6.0 569 -0.0522) t 0.0522 A 0.0047 + 0.0 522 2 [ Nacro ] 0.0 522 tit mor. (104:4+ 103:6)/1000 = 0. 251 monthit Now, CNO tho HCNO of our 1 0.2507 E (0.251 - x) X

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