Please help find the chemical formula of this unknown alcohol. What is known:
C% 70.53
H % 13.81
BP 156 C
Homework Answers
Given % of C = 70.53
% of H = 13.81
As it is alcohol, so there is O atom.
% of O = 100 - [70.53 + 13.81] = 15.66
Atomic mass of C = 12 g/mol, H = 1 g/mol, O = 16 g/mol
mol ratio of C : H : O = (70.53 / 12) : (13.81 / 1) : (15.66 / 16)
= 5.88 : 13.81 : 0.98
= (5.88 / 0.98) : (13.81 / 0.98) : (0.98 / 0.98) [dividing all by smallest number]
= 6 : 14 : 1
So molecular formula = C6H14O
Mass = (6*12) + (14*1) + (1*16) = 72+14+16 = 102 matches exactly
From boiling point data we can checked the structure as hexanol [CH3CH2CH2CH2CH2CH2OH]
So chemical formula is C6H14O
Add Answer to:
Please help find the chemical formula of this unknown alcohol.
What is known:
C% 70.53
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