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Time Remaining Return Next 39 1 point A 66.42-g sample of water is heated from 67.55...
A 66.52-g sample of water is heated from 71.33 °C to 80.96 °C. Calculate the energy absorbed by the water in joules. The specific heat of water is 4.20 J/g" in this temperature range. Do not type the units with your answer and use standard notation (not scientific). Type your answer.
Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is placed in a insulated container containing 128 g of water at a temperature of 21.4°C. After the metal cools, the final temperature of the metal and water is 25.0°C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings. Heat loss=Heat gained. Specific Heat Capacity of water is 4.18 J/g/K in this temperature range. Submit Answer Incompatible units....
Use the following experimental data to solve the questions below: mass of water = 98.731 g mass of goldfish before heating = 25.987 g specific heat of water = 4.184 J/g ⁰C mass of goldfish after heating = 25.761 g initial temperature of water = 21.31 ⁰C final temperature of water = 26.77 ⁰C A)Calculate the energy of the burning gold fish reaction (in Joules). Do not include units in your answer. Do not convert to scientific notation. No credit...
A 61.93 gram sample of iron (with a specific heat of 0.450 J/g °C) is heated to 100.0 °C. It is then transferred to a coffee cup calorimeter containing 40.6 g of water (specific heat of 4.184 J/ g °C) initally at 20.63 °C. If the final temperature of the system is 23.59, what was the heat absorbed (q) of the calorimeter? (total heat absorbed by the water and calorimeter = heat released by the iron)
A 48.79 g sample of metal is heated to 98.77oC and then quickly transferred to 88.34 mL of water at 24.65oC contained in a new calorimeter. This calorimeter has a calorimeter constant (heat capacity) with a numerical value of 55.7 (see problem 2e above for appropriate units). The thermal equilibrium temperature of the metal sample plus water mixture was 27.49oC. Assume the density of the water is 1.00 g/mL. a. How much heat in Joules is gained by the water?...
A 16.19 g sample of metal heated in a test tube submerged in 100.00 °C water. It was then placed directly into a coffee cup calorimeter holding 51.83 g of water at 22.09 °C. The temperature of the water increased to 24.51 °C, determine the specific heat capacity of the metal. 0.4294 If the calorimeter had absorbed 197.8 J and we factored that quantity into our calculations, what would the specific heat of the metal been? 1.69 9°C
A 21.3 g sample of a metal was heated to 61.67°C. When the metal was placed into 17.8 g of water in a calorimeter, the temperature of the water increased from 25.00°C to 30.00°C. What is the specific heat of th metal? The specific heat of water is 4.18 J/g. °C). Specific heat- J/g °C) Submit Answer Try Another Version 10 item attempts remaining
a 312 g sample of a metal is heated to 355.272 c A 312 g sample of a metal is heated to 355.272 °C and plunged into 200 g of water at a temperature of 45.471 °C. The final temperature of the water is 59.19 °C. Assuming water has a specific heat capacity of 4.184 J/g °C, what is the specific heat capacity of the metal sample, in J/g °C)? Assume no heat loss to the surroundings. Report your response...
Constants Part A A 235-g sample of a substance is heated to 320 °C and then plunged into a 105-g aluminum calorimeter cup containing 195 g of water and a 17-g glass thermometer at 10.5 ° C. The final temperature is 35.0° C. The value of specific heat for aluminium is 900 J/kg-C ,for glass is 840 J/kg . Co , and for water is 4186 J/kg-C" . What is the specific heat of the substance? (Assume no water boils...
What is the final temperature when a 10.0 g sample of water is heated with an input of 20.0 kJ starting at 10.0°C? You might need the following information for water: specific heat H2O(s): 2.09 J/g°C specific heat H2O(l): 4.18 J/g°C specific heat H2O(g): 1.84 J/g°C heat of fusion: 6.09 kJ/mole heat of vaporization: 40.7 kJ/mole Answer choices are: 488°C 273°C 89.0°C 100.°C It said 488 was wrong.