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Question 20 36.44 mL of NaOH are titrated with a known concentration of HCI (0.35M). Calculate...
A 50.00-ml NaOH sample of unknown concentration was titrated with 0.1274 M HCI.
Titrations 1. A 50.00-ml NaOH sample of unknown concentration was titrated with 0.1274 M HCI. if 33.61 mL of the HCl solution were required to neutralize the NaOH sample, what is the molarity of the NaOH sample? Show the steps in your calculation 2. A 25.00-ml HCl sample of unknown concentration was titrated with 0.5631 M Al(OH)3. If 37.62 mL of the Al(OH) solution were required to neutralize the HCl sample, what is the molarity of the HCl sample? (Assume Al(OH)3 is...
Concentration of Standardized HCI Solution = 0.39 Flask Mass Mg (g) 0.0845 0.0815 Volume HCI (mL)...
Concentration of Standardized HCI Solution = 0.39 Flask Mass Mg (g) 0.0845 0.0815 Volume HCI (mL) T 10mL 10mL 12.15 m2 Initial volume NaOH (mL) 21.15ML Final volume NaOH (ml) 21. 15m2 31.5mL Volume used NaOH (mL) 19 mL 10.35 ml CALCULATIONS **Show work for each trial.** . Moles of Mg used • Initial moles of HCl (total moles of HCl placed into each Erlenmeyer flask) • Moles of NaOH Moles of HCl titrated NaOH + HCI -----> NaCl +...
Concentration of Standardized HCI Solution = 0.934 M Flask 2 Mass Mg (8) 10.0849 0.0815 Volume...
Concentration of Standardized HCI Solution = 0.934 M Flask 2 Mass Mg (8) 10.0849 0.0815 Volume HCI (mL) I 10mL 10mL Initial volume NaOH (mL) 12.15ml Final volume NaOH (mL) 21.154L 9 m 21. 15ML 31.5mL 10.35 mL Volume used NaOH (mL) CALCULATIONS **Show work for each trial.** • Moles of Mg used Trial 0.084 Hy loola 10.001g Mg = 0.00 0.003375 mol My 0.0035 molto • Initial moles of HCl (total moles of HCl placed into each Erlenmeyer flask)...
Write the balanced equation occurring between HCl(aq) and NaOH(aq). a. It takes 15 mL of 0.125...
Write the balanced equation occurring between HCl(aq) and NaOH(aq). a. It takes 15 mL of 0.125 M NaOH to reach the end point of the reaction. How many moles of NaOH have you added? b. What is the mole ratio between HCl and NaOH? How many moles of HCI were in the titrated sample? c. At the beginning of the titration, there were 22 mL of HCl. What was the original concentration of HCl?
Exercise 14.48- Enhanced - with Feedback Four solutions of unknown NAOH concentration are titrated with...
Exercise 14.48- Enhanced - with Feedback Four solutions of unknown NAOH concentration are titrated with solutions of HCL The following table lists the volume of each unknown NAOH solution, the volume of HCl solution required to reach the equivalence point, and the concentration of each HCl solution. HCI (M) NAOH volume HCl volume (mL) (mL) 0.2099 8.00 8.97 11 14 0 1061 21.00 10 85 12.00 0.0889 35 18 29.00 0.1021 You may want to reference (Pages 494-497) Section 14.6...
A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution....
A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach equivalence point. In a separate titration, a 10.0 mL H3PO4 solution was titrated with the same NaOH solution. This time, 34.9 mL NaOH was required to reach the equivalence point. What is the concentration of the H3PO4 solution?
Exercise 14.47 Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following...
Exercise 14.47 Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCI solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution Part A Calculate the concentration (in M) of the unknown HCl solution in the first case. HCI Volume (ml) NaOH Volume (mL) (NaOH (M) 20.00 mL 27.44 mL 0.1191 M HCI Volume (mL) 20.00 mL 14.00 mL...
Exercise 14.47 Review Part Four solutions of unknown HCl concentration are titrated with solutions of NaOH....
Exercise 14.47 Review Part Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCI solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution. Calculate the concentration (in M) of the unknown HCl solution in the third case. HCI Volume (ml) NaOH Volume (mL) (NaOH (M) 24.00 mL 13.88 mL 0.1178 M Express your answer using four significant figures....
Concentration of NaOH Solution = 0.397 _M (from last week) 23 Trial # 1 Volume HCI...
Concentration of NaOH Solution = 0.397 _M (from last week) 23 Trial # 1 Volume HCI (mL) 10ml 1 ml 10mL 10mL 25.3 m2 19 mL Initial volume NaOH (mL) Final volume NaOH (mL) 25.3.149.3591/42.65mL Volume used NaOH (mL) 124.2m2 24.05mL | 23,65mL The following are the best three titration trials of NaOH that will be used in the Calculations Section: 24.2 m 24.05 mL 23.65 mL Volume of 6M HCl solution and diH2O needed to prepare 100mL of a...
Four solutions of unknown HCl concentration are titrated with solutions of NaOH.
Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCI solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution. Part BCalculate the concentration (in M) of the unknown HCl solution in the second case.
Concentration of Standardized HCI Solution = 0.39 Flask Mass Mg (g) 0.0845 0.0815 Volume HCI (mL) T 10mL 10mL 12.15 m2 Initial volume NaOH (mL) 21.15ML Final volume NaOH (ml) 21. 15m2 31.5mL Volume used NaOH (mL) 19 mL 10.35 ml CALCULATIONS **Show work for each trial.** . Moles of Mg used • Initial moles of HCl (total moles of HCl placed into each Erlenmeyer flask) • Moles of NaOH Moles of HCl titrated NaOH + HCI -----> NaCl +...
Concentration of Standardized HCI Solution = 0.934 M Flask 2 Mass Mg (8) 10.0849 0.0815 Volume HCI (mL) I 10mL 10mL Initial volume NaOH (mL) 12.15ml Final volume NaOH (mL) 21.154L 9 m 21. 15ML 31.5mL 10.35 mL Volume used NaOH (mL) CALCULATIONS **Show work for each trial.** • Moles of Mg used Trial 0.084 Hy loola 10.001g Mg = 0.00 0.003375 mol My 0.0035 molto • Initial moles of HCl (total moles of HCl placed into each Erlenmeyer flask)...
Write the balanced equation occurring between HCl(aq) and NaOH(aq). a. It takes 15 mL of 0.125 M NaOH to reach the end point of the reaction. How many moles of NaOH have you added? b. What is the mole ratio between HCl and NaOH? How many moles of HCI were in the titrated sample? c. At the beginning of the titration, there were 22 mL of HCl. What was the original concentration of HCl?
Exercise 14.48- Enhanced - with Feedback Four solutions of unknown NAOH concentration are titrated with solutions of HCL The following table lists the volume of each unknown NAOH solution, the volume of HCl solution required to reach the equivalence point, and the concentration of each HCl solution. HCI (M) NAOH volume HCl volume (mL) (mL) 0.2099 8.00 8.97 11 14 0 1061 21.00 10 85 12.00 0.0889 35 18 29.00 0.1021 You may want to reference (Pages 494-497) Section 14.6...
Exercise 14.47 Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCI solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution Part A Calculate the concentration (in M) of the unknown HCl solution in the first case. HCI Volume (ml) NaOH Volume (mL) (NaOH (M) 20.00 mL 27.44 mL 0.1191 M HCI Volume (mL) 20.00 mL 14.00 mL...
Exercise 14.47 Review Part Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCI solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution. Calculate the concentration (in M) of the unknown HCl solution in the third case. HCI Volume (ml) NaOH Volume (mL) (NaOH (M) 24.00 mL 13.88 mL 0.1178 M Express your answer using four significant figures....
Concentration of NaOH Solution = 0.397 _M (from last week) 23 Trial # 1 Volume HCI (mL) 10ml 1 ml 10mL 10mL 25.3 m2 19 mL Initial volume NaOH (mL) Final volume NaOH (mL) 25.3.149.3591/42.65mL Volume used NaOH (mL) 124.2m2 24.05mL | 23,65mL The following are the best three titration trials of NaOH that will be used in the Calculations Section: 24.2 m 24.05 mL 23.65 mL Volume of 6M HCl solution and diH2O needed to prepare 100mL of a...
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