Answer() Option A will produce result 8
Option(A)
def pass_it(x,y)
z = x**y // assume ** is exponentiation operator
// z = 23 = 8
return(z)
num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)
................................................................
Option(B)
def pass_it(x,y)
z = y**x; // assume ** is
exponentiation operator // z =
32 = 9
return(z)
num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)
.................................................................
Option(C)
def pass_it(x,y)
z = 2*3 // it is normal multiplication // z =
2*3 = 6
return(z)
num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)
.............................................................................
Option(D)
def pass_it(x,y)
z = x^y // it is XOR operation
// z = 2
XOR 3 = 1
// (10)2XOR
(11)2 =
(01)2
return(z)
num1=2
num2=3
answer= pass_it(num1,num2)
print(answer)
..................................................................................
Which of the following will result in an output of: 8 def pass_it(x, y): z =...
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