Question

6. Using any method, solve for V, the power supplied by the current source, and the power absorbed by each resistor. 60 30 mA 39 120

Answer 1

Given circuit can be simplified as shown. By using current division rule, let us find out the currents in the circuit.

6K Iz 18K + 3oma 312K 0.39K + 9k 30mA =loma = 180V I, = 30mA X 18K 20 mA (9K+18K) I2 = 30mA x OK (K+18) > Vo = 1,x9K = 20mA x9K Power suppued by 30mA current source = UX30mA = 180x30 mA = 5.4W Power absorbed by ak Resistor = I x9K = 20mA)?x9K = 3.6W Power absorbed by Power absorbed by 12k resistor 6K resistor = 12²x6k = TomA)²x6K = 0.66 = D_x12K - Roma)?x12K = loaw

Thus power supplied by current source =5.4 W

Power absorbed by the resistors = 3.6+0.6+1.2 =5.4 W

Hence power supplied = power absorbed . Hence Tellegen's theorem is also satisfied and we have the correct answer.