Question

1. Find the output voltage for these op amp circuits in standard configurations 2ke 10kr 3v Vout 5002 -M 5oor w Vout -2 po Sv

Answer 1

2K9 o w ov loke WWW b 3 V Voul It a By virtual grounding, voltage at node-b is o. hode- equation at b. Apply 0-3 O-Vout + =0 2k 10k 3 214 Yout TOK - Yout= -15V 5002 (2) 5oor -2V b Vout a + -2v virtual grounding By -2V voltage at b is Apply node. equation at 'b', -2 (-2-Vow) + 500 500 2+2 + Vout so Yout=-4V

(3) Voul. 7 く By Vicheal grounding, Voltage at b is 5V we that Can here See Vout =50 (1 f a lotus followel circuit). (u) 22 M ika M 2V ΟΥ b •Yout a 3ku WW 31 Buy 'ov' grounding Mirhial Coltug of b. is hode 6 node - Equation (KCL) at Apply O-2 0-34 O-Vout + + O 2K 3K Ik ( ) +61) Nout = -> Yout= -2v

2V 5 ww (6 ) 6 ike cm 2KL OV IKI w VA Youl + A + + lov VA It 18 a at b' is 'ov' By virdual glounding, coltage Apply node.equation at 'b'. O-10 o-VB at 50 ak IK VB = -10 - 10 ) VB = -5 V Then voltage at node-t is VBF-57. Now Apply hode equation at č. VB T VB-VA ak 1K -5-VA + درهم co => I VA = -7.5 V 2 21 from circuit we Can say Youut = VA. Vout= -7.5 V