Question

412 8.12 3812 24V 32H Answers must be in Amperes or Volts. Do not include the units in the blanks. Compute the following, immediately after the switch is closed (t=0). The currents at 422 2 at 812 & inductor o and at the outer 822 2 The voltages at 412 8 at inner 8Ω Ο , at the inductor 16 , and at the outer 812 16

Answer 1

ur 38r 82 w quv 12H not a long time. when the switch is closed the inductor does not have any Source & connected for : inductor Current is zero. (210-)=0 As inductor does allow Current to change abruptly, therefore and the current through inductor immediate after the switch is connected (closed) i įlot) = in (0)=0 A not 2 is zero : The circuit will become :- [immediate after sulitch is closed ur w mm zir or 240 와

current through ur Resistor, I = 24 = 2 A ut8 12 (as inductor does not have any Current Current through through inner &r & inductor ОА Current through outer or, I= 2 A [: same same as чC7 Veltage at ur, Vy = IX 4=2xU [ Vu= 8v voltage at inner 8r, Volim) Velim) = ov = 0x8 Voltage at inductor Vienductor) voltage across outer or = IX8 2x 8 Vinductor = 16V = voltage at outer 82, Noutardes) = 16V