Question

True or False Question A postmix beverage machine is adjusted to release a certain amount of syrup into a chamber where it is mixed with carbonated water. A random sample of 25 beverages was found to have a mean syrup content of 1.05 fluid ounces and a standard deviation of 0.15 fluid ounces. Assume that the syrup content of a beverage is normally distributed. Then, to check the claim that the syrup content per beverage is about one ounce, we use the following test H: N=1 against H:71. Based on the samples, the p-value for the test is less than 0.05. True False

Answer 1

Solution:

Correct ans is False

Given that,

=25 x = 1.05, 5=0.15 error Our UKE 0.03 95% U = I try on -1.05 2.064 x 0.03 = 1.05 + 0.062 F(0.988 1,112) HO:M=1 HIME ta X-M Strin HOS-1 1.667 0.03 Rejection A hagin t<2.064 FIT -2.064 +2.064 fail to reject to p-value 2P (E71,667) = 10.1085