Question

The length of a rectangle is 6 inches longer than it is wide. If the area is 55 square inches, what are the dimensions of the rectangle?

The width, or shorter side is___ inches

The length, or longer side is____ inches

Answer 1

let length of rectangle = 1 width of rectangle inches area = square => 155 Griven length is 6 inches longer than width (= 6+W We know, area of rectangle lew given 55 (1) (W): 55 (6+w) (W)=55 6W+w² whow-55=0. - w+ 11W-50-55=0 > WIW+11) - 5(W+1)=0 w 5)(+11)=0 - w-5=0 and w=5 W = -1 when w=5, l= 6+ w w+1=0 2 l=6+5 -> 1 = 1) when means W=-11 width is all, where with cannot be negative $0 ignore 5 inches Therefore, width or shorter side is length of longer side is 11 inches