Question

use at least 3 sig fig. I will rate

This pendulum is made from a 100-kg sphere and a 12-kg thin rod. Find the mass moment of inertia about an axis perpendicular to the page and passing through point A. Report your answer in kg-m2. A. 1 m R.2 m

Answer 1

Solution: Given, Thin rod, m = 12 Post l 1m sphere, М. R brool 100 The e = A. 0.5m de=0.5m da=3m mt=8 13m 62 Here, Tai Moment of Inertia of thin rod at centroid C (41) Iti = m ľ 12 -> Ich x 12x in 12 7 IGI = щ-

and Ina = Moment of inertia of sphere at centroid (G2 7 Ina ماه 2 5 MR" a 11 ? x 100 x 2 Ina 5 V I 160 kg-m² -G2 Howe, Mass moment of inertia about an axis Perpendicular to the page and through the point A, axis theoram, parallel By using (In tma Ig+mah) I. +md) Sphere CA Thin rod Juz + M da → In = (I 45, + m d) +

7 IA [Ia, + (12 x 0.5) +[Fe + (100 x 2) 7 IA = (1 +3) +1 160 + 900 7 I 4 + 1060 7 IA 1064 kg-m² Answer Note: parallex axis theoram. IA ={ (IG + ma' d )