Question

Develop an excel file to solve the following problem:

Air enters an adiabatic nozzle at 45 psia and 940F with a low velocity and exits at 650ft/s. Considering constant specific heats at room temperature, investigate the effect of the nozzle efficiency on the exit temperature (actual) and the pressure. Plot the temperatures, in degrees R (actual and isentropic) and the pressure, in psia as function of the nozzle efficiency. Vary the efficiency from 70% to 100%.

Repeat for an inlet temperature of 1000F.

Please can you make sure you do the repeat for an inlet for 1000F as well.

Answer 1

334.46 Bty Tom Given Pi=a5psia 2 solutions we will defermine the actual enthalpy at the exit from the initial enthalpy taken from AIFE f the actual exit velocity. hea - hi-va = 642.9-590? to be the The exit temperature is determined from the data in A17E using interpolations, Tra = Tit T2-T (haa-hi) Ti=940° h2-61 V2 = 650 RS 1360 R+ 1400-1360 834346-332-48) R = 40 to 100%. (342.9-332548 Tal = 1000F Taa= 136706R Answer to determine the final pressure the isenpropic enthalpy at the exit needs to be determined from the efficiency 34209 34209 - 334.46 ВЕЧ ebm has = 332 97 Btu/ebm 9 hi-hoa Here i - has= hit (hy h2a) – 0 chose =0.85 (blo wo 0170 to 1)- u can calculate at r any no value (0) = 38162 next we obtain the relative pressure for this enthappy from A17E using interpolation PR25 =Port Pre-Pri (125-hi) h2-hl 38141+ 42.88.– 38141... ( 332197- 832148 342.9 - 332.48 Pres finally the exit pressure is obtained from the ratio q the relati ve pressure f the initial pressure once again using data toom Pres A-17€. P2= Pi pr 42.88 Now for inlet temp q 1000°r poocedure + Calculate hd, from eq? O we get hea f from data table get tza (use eq? 2), has eq?3 , Praseqr4 ,P2 eq"5 = 38162 -x4spsia 40.53 psla= P2] 5 Answer we can CETIMIANTI

Hope it will help you... ...all the very best... comment below for any queries...thanks

I have provided all the formulas and sample calculation ...
Just change the efficiency value (0.70 to 1.00 ) in equation 3 ...to get different h2s values .... putting this in equation 4 gives gives Pr2s