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A bar of metal (length L =200 mm, diameter d=10 mm) is loaded axially by a tensile force P = 12 kN. If the bar elongates by 0

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Answer #1

The solution for calculating decrease in diameter d and value of modulus of elasticity is given below as image file

lomm 121 2 P Given data: - Q = 200mm = 0.2m d = 0.01m P = 12 KN a OOON se 0.3mm = 0.3% to 3m E 2 Sd shers o= = 12x1000 12000

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